Elementary Geometry for College Students (6th Edition)

Published by Brooks Cole
ISBN 10: 9781285195698
ISBN 13: 978-1-28519-569-8

Chapter 4 - Section 4.2 - The Parallelogram and Kite - Exercises - Page 186: 34

Answer

By definition of a kite we conclude that side BC=DC and BC=DC P= 2BC+2DC 59.2=4BC+10 49.2=4BC BC= 12.3

Work Step by Step

We can find $BC$: $P = AB+BC+CD+DA = 59.2$ $AB+BC+BC+AB = 59.2$ $(BC+5)+BC+BC+(BC+5) = 59.2$ $4~BC+10 = 59.2$ $4~BC = 49.2$ $BC = \frac{49.2}{4}$ $BC = 12.3$
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