Elementary Geometry for College Students (6th Edition)

Published by Brooks Cole
ISBN 10:
ISBN 13:

Chapter 3 - Section 3.5 - Inequalities in a Triangle - Exercises - Page 160: 34

Answer

See the picture below:
1503225432

Work Step by Step

Assuming, that $\overline{AC}=\overline{AB}=\overline{BC}$ triangle ABC is an equilateral triangle. This means $\angle ABC = 60^{\circ}$. But $\angle ABC = 90^{\circ}$ because ABCD is a square. Therefore $\overline{AC} \ne \overline {AB}$.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.