Elementary Geometry for College Students (6th Edition)

Published by Brooks Cole
ISBN 10:
ISBN 13:

Chapter 3 - Review Exercises - Page 166: 23

Answer

m$\angle$C=64$^{\circ}$

Work Step by Step

m$\angle$2=m$\angle$4 3x+10=$\frac{5}{2}$x+18 $\frac{1}{2}$x=8 x=16 m$\angle$2+m$\angle$4+m$\angle$C=180 3x+10+$\frac{5}{2}$x+18+m$\angle$C=180 3(16)+10+$\frac{5}{2}$(16)+18+m$\angle$C=180 116+m$\angle$C=180 m$\angle$C=64
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