Elementary Geometry for College Students (6th Edition)

Published by Brooks Cole
ISBN 10:
ISBN 13:

Chapter 11 - Review Exercises - Page 526: 32

Answer

$\sec\theta=\frac{61}{60}$ $\cot\theta=\frac{60}{11}$

Work Step by Step

$\tan\theta=\frac{11}{60}$ $\tan^2\theta+1=\sec^2\theta$ $\frac{121}{3600}+1=\sec^2\theta$ $\sec^2\theta=\frac{3721}{3600}$ $\sec\theta=\frac{61}{60}$ $\cot\theta=\frac{1}{\tan\theta}$ $\cot\theta=\frac{60}{11}$
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