Elementary Geometry for College Students (6th Edition)

Published by Brooks Cole
ISBN 10:
ISBN 13:

Chapter 11 - Review Exercises - Page 525: 23


The angle of elevation to the top of the wall is $41^{\circ}$.

Work Step by Step

Refer to the attachment for variables: 1. Use the sine law to find $\angle C$ $\frac{sinC}{3} = \frac{sin90}{4}$ $sinC = \frac{3sin90}{4}$ $sinC = \frac{3}{4}$ $C = sin^{-1}(\frac{3}{4})$ $C = 48.590...^{\circ}$ 2. Find $\angle α$ $\angle α = 180 - (48.590... + 90)$ $\angle α = 180 - 138.590...$ $\angle α = 41.409...^{\circ}$ $\angle α \approx 41^{\circ}$
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