#### Answer

The midpoints of quadrilaterals form a parallelogram.

#### Work Step by Step

We assign coordinates for each point on quadrilateral ABCD:
$A: 0,0 \\ B: 2a, 2b \\ C: 2c, 2d \\ D: 2e, 0$
This means that the midpoints are:
$(a,b); (a+c, b+d); (e,0); (e+c, d)$
Thus, the slopes are:
$m_1 = \frac{b+d-b}{a+c-c} =\frac{d}{c}$
$m_2 = \frac{b+d-d}{a+c-e-c} =\frac{b}{a-e}$
$m_3 = \frac{d-0}{e+c-e} =\frac{d}{c}$
$m_4 = \frac{b-0}{a-e} =\frac{b}{a-e}$
Since corresponding slopes are equal, the figure inside of the quadrilateral is a parallelogram.