Elementary Geometry for College Students (6th Edition)

Published by Brooks Cole
ISBN 10: 9781285195698
ISBN 13: 978-1-28519-569-8

Chapter 10 - Section 10.2 - Graphs of Linear Equations and Slope - Exercises - Page 450: 12c


$\frac{8\sqrt 6}{\sqrt 2}$ =8$\sqrt 3$

Work Step by Step

(2$\sqrt 2$,-3$\sqrt 6$) and (3$\sqrt 2$,5$\sqrt 6$) x1=2$\sqrt 2$, y1=-3$\sqrt 6$,x2=3$\sqrt 2$,y2=5$\sqrt 6$ Using slope formula m = $\frac{y2-y1}{x2-x1}$ m= $\frac{5\sqrt 6+3\sqrt 6}{3\sqrt 2-2\sqrt 2}$ = $\frac{8\sqrt 6}{\sqrt 2}$ =8$\sqrt 3$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.