#### Answer

The triangle is an isosceles triangle.

#### Work Step by Step

We find the lengths of the sides:
$AB = \sqrt{(-6-3)^2 + (4-6)^2} = \sqrt{85}$
$BC= \sqrt{(-6-1)^2 + (4-(-2))^2} = \sqrt{85}$
Since two sides are of equal lengths, the triangle is an isosceles triangle.