## Elementary Geometry for College Students (6th Edition)

We find the lengths of the sides: $AB = \sqrt{(-6-3)^2 + (4-6)^2} = \sqrt{85}$ $BC= \sqrt{(-6-1)^2 + (4-(-2))^2} = \sqrt{85}$ Since two sides are of equal lengths, the triangle is an isosceles triangle.