Elementary Geometry for College Students (6th Edition)

Published by Brooks Cole
ISBN 10:
ISBN 13:

Chapter 10 - Review Exercises - Page 486: 19

Answer

The triangle is an isosceles triangle.

Work Step by Step

We find the lengths of the sides: $AB = \sqrt{(-6-3)^2 + (4-6)^2} = \sqrt{85}$ $BC= \sqrt{(-6-1)^2 + (4-(-2))^2} = \sqrt{85}$ Since two sides are of equal lengths, the triangle is an isosceles triangle.
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