Elementary Geometry for College Students (6th Edition)

Published by Brooks Cole
ISBN 10:
ISBN 13:

Chapter 1 - Section 1.4 - Angles and Their Relationships - Exercises - Page 36: 31

Answer

x=143$^{\circ}$

Work Step by Step

x=(90$^{\circ}$-$\angle$PNQ)+92$^{\circ}$ x=(90$^{\circ}$-39$^{\circ}$)+92$^{\circ}$ x=51$^{\circ}$+92$^{\circ}$ x=143$^{\circ}$
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