Elementary Geometry for College Students (6th Edition)

Published by Brooks Cole
ISBN 10: 9781285195698
ISBN 13: 978-1-28519-569-8

Chapter 1 - Section 1.3 - Early Definitions and Postulates - Exercises - Page 28: 41


$NM = \frac{1}{3}a+\frac{1}{2}b$

Work Step by Step

We can find the length of NM: $NM = NB + BM$ $NM = (AB-AN)+BM$ $NM = (a - \frac{2}{3}a)+\frac{1}{2}b$ $NM = \frac{1}{3}a+\frac{1}{2}b$
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