Answer
$12+10i$
Work Step by Step
Note: the standard form of a complex number is $a+bi$ where $i = \sqrt -1$ and $a$ and $b$ are real numbers.
Note: $i^{2} = \sqrt -1\sqrt -1 = -1$
$7+4i+i(6-5i)$
First, expand out the complex number:
$7+4i+6i-5i^{2}$
As seen in the note above, $i^{2} = -1$, so substitute in $-1$.
$7+ 4i+6i-5(-1)$
$7+4i+6i+5$
Combine like terms, to express the complex number in standard form:
$12+10i$
