Answer
$\mathcal{B}$ is not a basis of $M_{22}$.
Work Step by Step
The vector space $M_{22}$ has dimension $4$. So, any set of vectors of cardinality greater than $4$ must be linearly dependent. Since $\mathcal{B}$ has $5$ elements, $\mathcal{B}$ cannot a basis of $M_{22}$.