Linear Algebra: A Modern Introduction

Published by Cengage Learning
ISBN 10: 1285463242
ISBN 13: 978-1-28546-324-7

Chapter 4 - Eigenvalues and Eigenvectors - 4.6 Applications and the Perron-Frobenius Theorem - Exercises 4.6 - Page 361: 47

Answer

See below.

Work Step by Step

If $x_n=x_{n-1}-x_{n-2}$ and $x_0=1,x_1=1$, then: $x_2=x_1-x_0=1-0=1$ $x_3=x_2-x_1=1-1=0$ $x_4=x_3-x_2=0-1=-1$ $x_5=x_4-x_3=-1-0=-1$ $x_6=x_5-x_4=-1-(-1)=0$ $x_7=x_6-x_5=0-(-1)=1$
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