Linear Algebra: A Modern Introduction

Published by Cengage Learning
ISBN 10: 1285463242
ISBN 13: 978-1-28546-324-7

Chapter 4 - Eigenvalues and Eigenvectors - 4.2 Determinants - Exercises 4.2 - Page 282: 49

Answer

$-\frac{3}{2}$

Work Step by Step

We know that if $A$ and $B$ are $n\times n$ matrices, then $det(AB)=det(A)det(B)$. We also know that if $A$ is invertible, then $det(A^{-1})=\frac{1}{det(A)}$ Hence $det(B^{-1}A)=det(B^{-1})det(A)=\frac{1}{det(B)}det(A)=\frac{1}{-2}\cdot3=-\frac{3}{2}$
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