## Linear Algebra: A Modern Introduction

$\frac{5}{-5}$
1) d-c=$[\frac{3}{-2}]$-$[\frac{-2}{3}]$=$[\frac{5}{-5}]$ 2) To obtain result geometrically, draw vector d in standard position. After that draw vector -c such that the tail of -c is the same point as the head of d. Then, vector d-c has tail at origin and head at the same point as -c has. 3) See diagram