#### Answer

$-ie^2$

#### Work Step by Step

$e^{2-i(\frac{\pi}{2})} = e^2e^{-i\frac{\pi}{2}}$
Applying Euler's equation to $cos(-\frac{\pi}{2}) + isin(-\frac{\pi}{2}))$
$cos(-\frac{\pi}{2}) = 0, isin(-\frac{\pi}{2}) = - i$
$-ie^2$

Published by
Wiley

ISBN 10:
0-47038-334-8

ISBN 13:
978-0-47038-334-6

$-ie^2$

You can help us out by revising, improving and updating this answer.

Update this answerAfter you claim an answer you’ll have **24 hours** to send in a draft. An editor
will review the submission and either publish your submission or provide feedback.