Answer
$(x+2)^{2}+(y-1)^{2}\lt 6$
Work Step by Step
The circle with center $C(h,k)$ and radus $a$ has the general equation
$( x-h)^{2}+(y-k)^{2}=a^{2}.$
The border curve between the interior and exterior is the circle itself.
$(x+2)^{2}+(y-1)^{2}=6$.
The center belongs to the interior, and its coordinates satisfy the inequality
$(-2+2)^{2}+(1-1)^{2}=0\lt 6, $
So all interior points will satisfy:
$(x+2)^{2}+(y-1)^{2}\lt 6$
