University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter 9 - Section 9.9 - Convergence of Taylor Series - Exercises - Page 542: 37

Answer

$|x| \lt 0.56968$

Work Step by Step

The Taylor series for $\sin x $ can be defined as: $\sin x= x-\dfrac{x^3}{3!}+\dfrac{ x^5}{5!}-....$ and $\sin x= x-\dfrac{x^3}{6}+\dfrac{ x^5}{120}-....$ We need to find $ x $. $\dfrac{|x|^5}{5!} \lt 5 \times 10^{-4} $ or, $|x|^5 \lt 5! \times 5 \times 10^{-4} $ or, $|x| \lt 0.56968$
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