#### Answer

Converges

#### Work Step by Step

Since, the given series is a geometric series with common ratio $r=\dfrac{1}{e}$
Thus, for this series $|r|=\dfrac{1}{e} \lt 1$
Hence, the given series converges.

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Published by
Pearson

ISBN 10:
0321999584

ISBN 13:
978-0-32199-958-0

Converges

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