Answer
$\dfrac{e^2}{e^2-1}$
Work Step by Step
The sum of a geometric series can be found as:
$S=\dfrac{a}{1-r}$
We have a convergent geometric series with first term, $a=1$ and common ratio $r =\dfrac{1}{e^2}$
Thus, $S=\dfrac{1}{1-(\dfrac{1}{e^2})}=\dfrac{e^2}{e^2-1}$
