University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter 9 - Section 9.10 - The Binomial Series and Applications of Taylor Series - Practice Exercises - Page 553: 51



Work Step by Step

Since, we have the form of the given series as: $\dfrac{1}{1+x}=1-x+x^2-x^3+....+(-x)^n$ Here, $x=\dfrac{1}{4}$ Thus, the sum of the series is: $\dfrac{1}{1+\dfrac{1}{4}}=\dfrac{4}{4+1}=\dfrac{4}{5}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.