University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter 9 - Section 9.1 - Sequences - Exercises - Page 489: 108

Answer

Proof given below.

Work Step by Step

Let $L=\displaystyle \lim_{n\rightarrow\infty}(x)^{1/n}$, for a positive number $x$ $ L=\displaystyle \lim_{n\rightarrow\infty}(x)^{1/n}\qquad$ ...apply ln(..) to both sides $\displaystyle \ln L=\ln[\lim_{n\rightarrow\infty}(x)^{1/n}]\qquad$ ... ln is continuous $\displaystyle \ln L=\lim_{n\rightarrow\infty}[\ln(x)^{1/n}]$ $\displaystyle \ln L=\lim_{n\rightarrow\infty}[\frac{1}{n}\ln x]\qquad$... $\ln x$ is constant when $ n\rightarrow\infty$ $\displaystyle \ln L=\ln x\cdot\lim_{n\rightarrow\infty}[\frac{1}{n}]$ $\ln L=\ln x\cdot 0$ $\ln L=0$ $L=1$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.