University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter 9 - Practice Exercises - Page 552: 1


Sequence converges to $1$.

Work Step by Step

As we know that a sequence converges when $\lim\limits_{n \to \infty}a_n$ exists. Consider $a_n=1+\dfrac{(-1)^n}{n}$ Apply limits to both sides. $\lim\limits_{n \to \infty}a_n=\lim\limits_{n \to \infty}[1+\dfrac{(-1)^n}{n}]$ $\lim\limits_{n \to \infty}a_n=[\lim\limits_{n \to \infty}1+\lim\limits_{n \to \infty}\dfrac{(-1)^n}{n}]$ $\lim\limits_{n \to \infty}a_n=1+\dfrac{1}{\infty}$ $\lim\limits_{n \to \infty}a_n=1+0$ $\lim\limits_{n \to \infty}a_n=1$ Hence, the sequence converges to $1$.
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