University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter 8 - Section 8.2 - Trigonometric Integrals - Exercises - Page 434: 1


$\frac{1}{2}sin 2x+C$

Work Step by Step

Let I= $\int cos 2xdx$ Plug in: 2x=u $⇒dx= \frac{du}{2}$ Then: $I=\int cos u \frac{du}{2}$ $= \frac{1}{2}\int cos u du$ $= \frac{1}{2}\times sin u +C$ $= \frac{1}{2}sin 2x +C$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.