University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter 6 - Section 6.5 - Work - Exercises - Page 382: 31

Answer

$5.144 \times 10^{10}$ joules

Work Step by Step

Here, we have $W=\int_a^b\dfrac{mMG}{r^2}dr$ or, $W=\dfrac{mMG}{\dfrac{1}{a}}-\dfrac{mMG}{\dfrac{1}{b}}$ This implies that $W=mMG(\dfrac{1}{a}-\dfrac{1}{b})$ Plug in the values. $W=(1000)(5.975 \times 10^{24}) (6.6720 \times 10^{-11})(\dfrac{1}{6370000}-\dfrac{1}{35780000})$ Thus, $W=5.144 \times 10^{10}$ joules
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