University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter 6 - Section 6.5 - Work - Exercises - Page 380: 6


$18.75$ in-lb

Work Step by Step

We know that Hooke's Law states that $F=k x$ Then, $x=\dfrac{F}{k}=\dfrac{150}{1/16}=2400$ m Thus, $F=2400 x \implies F(1/8)=2400 \times (1/8)=300$lb To calculate the work done, the limits for $x$ will be from $0$ to $1/8$ such that: $W=\int_0^{1/8} 2400 x=2400[ \dfrac{x^2}{2}]_0^{1/8}$ or, $W=1200[ (1/8)^2-0] =18.75$ in-lb
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