Answer
$$8 \pi \sqrt 5$$
Work Step by Step
We need to compute the surface area.
$$S= \int_{m}^{n} 2 \pi y \sqrt {1+(y')^2}$$ $$\\=(2 \pi)\int_{0}^{2}(2y) \times \sqrt {1+(2)^2} dy \\=[4 \pi \sqrt 5y]_{0}^{2}\\=8 \pi \sqrt 5$$
University Calculus: Early Transcendentals (3rd Edition)
by Hass, Joel R.; Weir, Maurice D.; Thomas Jr., George B.
Published by
Pearson
ISBN 10:
0321999584
ISBN 13:
978-0-32199-958-0
Chapter 6 - Section 6.4 - Areas of Surfaces of Revolution - Exercises - Page 375: 10
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
