University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter 6 - Section 6.2 - Volumes Using Cylindrical Shells - Exercises - Page 363: 1

Answer

$6 \pi$

Work Step by Step

Consider the shell model to compute the volume: $V=\int_{m}^{n} (2 \pi) (\space Radius \space of \space shell) \times ( height \space \text{of} \space \text {shell}) dx \\=\int_0^{2} (2 \pi) \cdot x (1+\dfrac{x^2}{4}) dx \\= \int_0^{2} (2 \pi ) (x+\dfrac{x^3}{4}) dx\\= [\dfrac{(2\pi ) x^2}{2}+\dfrac{(2\pi ) x^4}{16}]_0^{2} dx \\=6 \pi$
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