Answer
$$15$$
Work Step by Step
We need to integrate the integral to compute the volume.
$$ \space Volume = \int_{0}^{5} (\dfrac{9}{25}) (5-z)^2 dz \\=-\dfrac{-3}{25}(5-z)^3]_{0}^{5} \\= (-\dfrac{3}{25}) (0-125) \\=15$$
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