University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter 5 - Section 5.5 - Indefinite Integrals and the Substitution Method - Exercises - Page 329: 1



Work Step by Step

$u=2x+4$, therefore $du=2dx$. Let's rewrite the integral! $\int (2(2x+4)^5)dx=\int ((2x+4)^5)2dx$ We do the substitution! $\int ((2x+4)^5)2dx=\int u^5du=\frac{u^6}{6}+c$ We re-do the substitution! $\frac{u^6}{6}+c=\frac{(2x+4)^6}{6}+c$
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