Chapter 5 - Section 5.5 - Indefinite Integrals and the Substitution Method - Exercises - Page 329: 1

$\frac{(2x+4)^6}{6}+c$

$u=2x+4$, therefore $du=2dx$. Let's rewrite the integral! $\int (2(2x+4)^5)dx=\int ((2x+4)^5)2dx$ We do the substitution! $\int ((2x+4)^5)2dx=\int u^5du=\frac{u^6}{6}+c$ We re-do the substitution! $\frac{u^6}{6}+c=\frac{(2x+4)^6}{6}+c$