University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter 5 - Section 5.3 - The Definite Integral - Exercises - Page 311: 88


$37.5$ miles per hour

Work Step by Step

Let $t_1$ be the time is taken for the forward trip: Then, $t_1=\dfrac{150}{30}=5 hrs$ Let $t_2$ be the time is taken for the return trip: Then, $t_2=\dfrac{150}{50}=3 hrs$ Now, $t_1+t_2=8 hrs$ Total distance =150 +150=300 miles Thus, the total time taken is: $T=\dfrac{300}{8}=37.5$ miles per hour
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