Answer
$\int_{2}^{3}\frac{1}{1-x} dx$.
Work Step by Step
By using the definition of the definite integral, P is a partition of [2,3], therefore the lower and upper limits of the integration are 2 and 3. $f(c_{k})=\frac{1}{1-c_{k}}$ is the function in the additive of the Riemann sums, therefore $f(x)=\frac{1}{1-x}$. Therefore the solution is: $\int_{2}^{3}\frac{1}{1-x} dx$.
