University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter 5 - Questions to Guide Your Review - Page 341: 4

Answer

$||P||=max$ {$x_1-x_0, x_2-x_1, ....,x_n-x_{n-1} $}

Work Step by Step

The mesh or norm of a partition of a closed interval $[a,b]$ is denoted as $||P||$ and can be defined as $||P||=max$ {$x_1-x_0, x_2-x_1, ....,x_n-x_{n-1} $} where, $a=x_0 \lt x_1 \lt x_2 \lt ....\lt x_{i-1} \lt x_i \lt ....\lt x_{n-1} \lt x_n=b$
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