## University Calculus: Early Transcendentals (3rd Edition)

$10 \tan (s/10)+c$
Calculate the anti-derivative for $\int \sec^2 (s/10) ds$ Since, we know $\int \sec^2 x =\tan x$ $\int \sec^2 (s/10) ds=\dfrac{1}{1/10} \tan (s/10)+c$ or, $=10 \tan (s/10)+c$