University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter 4 - Practice Exercises - Page 278: 107


$10 \tan (s/10)+c$

Work Step by Step

Calculate the anti-derivative for $\int \sec^2 (s/10) ds$ Since, we know $\int \sec^2 x =\tan x$ $\int \sec^2 (s/10) ds=\dfrac{1}{1/10} \tan (s/10)+c$ or, $=10 \tan (s/10)+c$
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