Answer
$10 \tan (s/10)+c$
Work Step by Step
Calculate the anti-derivative for $\int \sec^2 (s/10) ds$
Since, we know $\int \sec^2 x =\tan x$
$\int \sec^2 (s/10) ds=\dfrac{1}{1/10} \tan (s/10)+c$
or, $=10 \tan (s/10)+c$
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