University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter 3 - Section 3.4 - The Derivative as a Rate of Change - Exercises - Page 144: 9

Answer

The time it takes the rock to reach a velocity of $27.8m/s$ on Mars is approximately $7.473$ seconds and on Jupiter is approximately $1.215$ seconds.

Work Step by Step

1) On Mars: $$s(t)=1.86t^2$$ - Velocity: $v(t)=\frac{ds}{dt}=(1.86t^2)'=3.72t$ The time it takes for $v(t)$ to reach $27.8m/s$ is $$3.72t=27.8$$ $$t\approx7.473s$$ 2) On Jupiter: $$s(t)=11.44t^2$$ - Velocity: $v(t)=\frac{ds}{dt}=(11.44t^2)'=22.88t$ The time it takes for $v(t)$ to reach $27.8m/s$ is $$22.88t=27.8$$ $$t\approx1.215s$$
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