## University Calculus: Early Transcendentals (3rd Edition)

change in volume percent: $\frac{dV}{V}=40%$
We are given: $V=kr^4$ relative change for the function is shown by the relation: $\frac{dV}{V}$ $\frac{dV}{V}=\frac{4kr^3dr}{kr^4}$ $\frac{dV}{V}=\frac{4dr}{r}$ it is given that the increase in the value of r is 10%: so $dr=0.1r$ $\frac{dV}{V}=\frac{4\times0.1r}{r}=0.4$ $\frac{dV}{V}=0.4\times100=40%$ $\frac{dV}{V}=40%$