University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter 16 - Section 16.1 - Solutions, Slope Fields, and Euler's Method - Exercises - Page 16-8: 10


$\dfrac{dy}{dx}=y$ and $y(0)=1$

Work Step by Step

In order to determine the differential equation, we will have to take the derivative of the differential equation. Here, we have: $\dfrac{dy}{dx}=0+y(x)$ or, $\dfrac{dy}{dx}=y$ Apply the initial conditions: Then, we have $y(0)=1$ Hence, our answers are: $\dfrac{dy}{dx}=y$ and $y(0)=1$
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