University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter 15 - Section 15.4 - Green's Theorem in the Plane - Exercises - Page 862: 21

Answer

$0$

Work Step by Step

Green Theorem, Tangential form for Counterclockwise Circulation, can be defined as: $\oint_C F \cdot T ds= \iint_{R} (\dfrac{\partial N}{\partial x}-\dfrac{\partial M}{\partial y}) \space dx \space dy $ Now, $$\oint_C F \cdot n ds= \iint_{R} \dfrac{\partial (x^2)}{\partial x}-\dfrac{\partial (y^2)}{\partial y} dx dy \\= \int_{0}^1 \int_0^{1-x} 2x-2y dx dy \\= \int_{0}^1 \int_0^{1-x} [2x-2y] dx dy \\= \int_{0}^1 4x-3x^2-1 dx \\=[2x^2-x^3-x]_0^1 \\=0$$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.