University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter 15 - Section 15.4 - Green's Theorem in the Plane - Exercises - Page 861: 5

Answer

Outward flux $=2$ and Counterclockwise Circulation =0

Work Step by Step

Green's Theorem Normal form for outward Flux is: $=\oint_C F \cdot n ds= \iint_{R} (\dfrac{\partial N}{\partial x}-\dfrac{\partial M}{\partial y}) \space dx \space dy$ or, $= \iint_{R} (\dfrac{\partial (x-y)}{\partial x}-\dfrac{\partial (y-x)}{\partial y}\space dx \space dy$ or, $=2 \iint_{R} dx dy $ or, $=2$ Green Theorem -Tangential form for Counterclockwise Circulation is: $\oint_C F \cdot T ds= \iint_{R} (\dfrac{\partial N}{\partial x}-\dfrac{\partial M}{\partial y}) \space dx \space dy$ $= \iint_{R} \dfrac{\partial (y-x)}{\partial x}-\dfrac{\partial (x-y)}{\partial y} dx dy$ or, $=\iint_{R} -1 -(-1) \space dx \space dy=0 $
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