University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter 15 - Section 15.2 - Vector Fields and Line Integrals: Work, Circulation, and Flux - Exercises - Page 840: 48

Answer

$24$

Work Step by Step

Flow $=\int_C F(r(t)) \dfrac{dr}{dt}(dt)$ and $ \dfrac{dr}{dt}= 3 j+4 k$ Then , flow $=\int_0^{1}(12t^2 j+9t^2 k) (3 j+4 k)dt$ or, $= \int_0^{1}36t^2+36t^2 dt$ or, $=[ 24t^3]_0^{1}$ or, $=24$
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