Answer
$0$
Work Step by Step
Since, we have $\int_C F \cdot T ds-\int_C F. dr=\int_C (x+y) dx +(x+y) dy$
Now,
$\int_C (x+y) dx +(x+y) dy=\int_0^{2\pi}(2 \cos t +2\sin t) (-2 \sin t dt ) +(2 \cos t +2\sin t) (2 \cos t dt ) $
$=\int_{0}^{2\pi} 4 \cos 2t dt$
or, $=0$
