Answer
$0$
Work Step by Step
We set up three parametric equations:
$x=-1+5t$
$y=1-4t$
$z=1-t$
$ dx= 5 dt, dy=-4 dt$ and $dz=-dt$
Plug in the above values in the given integral.
$\int_{-1,1,1}^{4-3,0} \dfrac{5dt-4dt-dt}{\sqrt {(-1+5t)+(1-4t)+(1-t)}}$
Thus, we have
$\int_{0}^{1}\dfrac{0}{\sqrt {1+0t}}dt=0$
