Answer
$ 3 \ln 2-\dfrac{3}{2}$
Work Step by Step
Re-arrange the given integral as follows:
$\int_{1}^{2} [\ln y ] dx=[y \ln y]_{1}^{2} - \int_{1}^{2} (1) dx$
This implies that
$[y \ln y]_{1}^{2} - \int_{1}^{2} (1) dx= 3 \ln 2-\dfrac{3}{2}$
University Calculus: Early Transcendentals (3rd Edition)
by Hass, Joel R.; Weir, Maurice D.; Thomas Jr., George B.
Published by
Pearson
ISBN 10:
0321999584
ISBN 13:
978-0-32199-958-0
Chapter 14 - Section 14.1 - Double and Iterated Integrals over Rectangles - Exercises - Page 759: 14
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