University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter 14 - Practice Exercises - Page 816: 1

Answer

$9(e-1)$

Work Step by Step

The region of integration can be expressed as: $R=${$ (x,y) | 0 \leq x \leq 1/y, 1 \leq y \leq 10$} Consider $I=\int_{1}^{10} \int_{0}^{1/y} ye^{xy} \ dx \ dy$ or, $=\int_{1}^{10} [e^{xy}]_{0}^{1/y} \ dy$ or, $=\int_{1}^{10} (e-1) \ dy$ or, $=[(e-1)y]_{1}^{10}$ or, $=10(e-1)-(e-1)$ or, $=9(e-1)$
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