University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter 13 - Section 13.8 - Lagrange Multipliers - Exercises - Page 746: 2

Answer

$(\pm \sqrt 5, \sqrt 5) $ and $(\pm \sqrt 5,-\sqrt 5)$

Work Step by Step

As we are given that $f(x,y) =xy$ and the equation of constraint $g(x,y)=x^2+y^2-10=0$ since, we have the gradient equation $\nabla =\lambda \nabla g$ Now, $y=2 \lambda x \implies y=\pm \dfrac{1}{2}$ and $x=2 \lambda y \implies x=\pm y$ Now, $g(x,y)=x^2+y^2-10=0 \implies y= \pm \sqrt 5; x=\pm \sqrt 5$ Hence, our points are: $(\pm \sqrt 5, \sqrt 5) $ and $(\pm \sqrt 5,-\sqrt 5)$
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