Answer
$0.0222$
Work Step by Step
$f_x=e^x \cos y \\ \implies f_x(0,0)=e^{0} \cos 0=1$
Next, $f_y(x,y) =-e^x \sin y \\ \implies f_{y}(0,0) =0$
$f_{xx}(x,y)=-e^x \cos y; f_{yy}(x,y)=-e^x \cos y$ and $f_{xy}(x,y) =-e^x \sin y$
The error can be found as:
$|E(x,y)| \leq \dfrac{1}{2} \times (1.11) [ |x-0| +|y-0|)^2$
$\implies E \leq \dfrac{1.11}{2} \times (0.1+0.1)^2 =0.0222$