Answer
(a) $3$ and (b) $2$
Work Step by Step
(a) The slope of the line tangent to a surface $f(x,y)$ at the point $(a,b)$ and lying in the plane $x=a$ is given as $f_y(a,b)$.
Thus, $f_y(x,y)=3 \implies f_y(-2,1)=3$
(b) The slope of the line tangent to a surface $f(x,y)$ at the point $(a,b)$ and lying in the plane $y=b$ is given as $f_x(ab)$.
Thus, $f_x(x,y)=2 \implies f_x(-2,1)=2$