University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter 13 - Section 13.3 - Partial Derivatives - Exercises - Page 703: 61

Answer

(a) $3$ and (b) $2$

Work Step by Step

(a) The slope of the line tangent to a surface $f(x,y)$ at the point $(a,b)$ and lying in the plane $x=a$ is given as $f_y(a,b)$. Thus, $f_y(x,y)=3 \implies f_y(-2,1)=3$ (b) The slope of the line tangent to a surface $f(x,y)$ at the point $(a,b)$ and lying in the plane $y=b$ is given as $f_x(ab)$. Thus, $f_x(x,y)=2 \implies f_x(-2,1)=2$
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