University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter 13 - Section 13.2 - Limits and Continuity in Higher Dimensions - Exercises - Page 690: 4



Work Step by Step

Solve the limit $\lim\limits_{(x,y) \to (2,-3)} (\dfrac{1}{x}+\dfrac{1}{y})^2$ $\lim\limits_{(x,y) \to (2,-3)} (\dfrac{1}{x}+\dfrac{1}{y})^2=(\dfrac{1}{2}+\dfrac{1}{(-3)})^2$ or, $(\dfrac{1}{6})^2=\dfrac{1}{36}$
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