Answer
$\dfrac{1}{36}$
Work Step by Step
Solve the limit $\lim\limits_{(x,y) \to (2,-3)} (\dfrac{1}{x}+\dfrac{1}{y})^2$
$\lim\limits_{(x,y) \to (2,-3)} (\dfrac{1}{x}+\dfrac{1}{y})^2=(\dfrac{1}{2}+\dfrac{1}{(-3)})^2$
or, $(\dfrac{1}{6})^2=\dfrac{1}{36}$
