University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter 13 - Practice Exercises - Page 752: 91

Answer

$b \dfrac{\partial w}{\partial x}=a \dfrac{\partial w}{\partial y} $

Work Step by Step

Since, $\dfrac{\partial u}{\partial y}=b$ and $\dfrac{\partial u}{\partial x}=a$ Now, $\dfrac{\partial w}{\partial x}=\dfrac{\partial w}{\partial u} \ \dfrac{\partial u}{\partial x}=a \dfrac{\partial w}{\partial u}...(1)$ and $\dfrac{\partial w}{\partial y}=\dfrac{\partial w}{\partial u} \ \dfrac{\partial u}{\partial y}=b \dfrac{\partial w}{\partial u}...(2)$ Equation (1) and (2) can be written as: $\dfrac{1}{a} \dfrac{\partial w}{\partial x}=\dfrac{\partial w}{\partial u}$ and $\dfrac{1}{b} \dfrac{\partial w}{\partial y}=\dfrac{\partial w}{\partial u}$ This implies that $\dfrac{1}{a} \dfrac{\partial w}{\partial x}=\dfrac{1}{b} \dfrac{\partial w}{\partial y}$ Therefore, $b \dfrac{\partial w}{\partial x}=a \dfrac{\partial w}{\partial y} $
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