Answer
$15.83 \% $
Work Step by Step
We can write as: $dI=\dfrac{dV}{R}-\dfrac{V \ dR}{R^2}$
and at $(24,100)$, we have: $dI=\dfrac{dV}{100}-\dfrac{24 \ dR}{(100)^2}$
When $v=-1, dR=-20$
So, $dI=-0.01+480(0.0001)=0.038$
The estimated change in $I$ is:
$I=\dfrac{dI}{I} \times 100=\dfrac{0.038}{0.24} \times 100 \approx 15.83 \% $
